What is the derivative of 2(x-1^2) ?

The derivative of 2(x-1^2) is 4(x-1)

What is the first derivative of 2(x-1^2) ?

The first derivative of 2(x-1^2) is 4(x-1)

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\frac{d}{d x} (2 (x - 1)^{2})

4 (x - 1)

Solution steps

\frac{d}{d x} (2 (x - 1)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x - 1)^{2})

Apply the chain rule:

2 (x - 1) \frac{d}{d x} (x - 1)

= 2 (x - 1) \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 2 \cdot 2 (x - 1) \cdot 1

Simplify

= 4 (x - 1)

y^{^{''}} + 4 y^{^{'}} + 5 y = - 10 x + 3 e^{- x}

x \to 3 lim (x - 2)

\int \frac{sec ^{2} ( x )}{x} d x

f (x) = \frac{x + 5}{x - 5}

x \to - 2 lim (x^{2} - \frac{4}{x + 2})

What is the derivative of 2(x-1^2) ?
The derivative of 2(x-1^2) is 4(x-1)
What is the first derivative of 2(x-1^2) ?
The first derivative of 2(x-1^2) is 4(x-1)