What is the solution for (dy)/(dx)+3y=e^{4x} ?

The solution for (dy)/(dx)+3y=e^{4x} is y=(e^{4x})/7+(c_{1})/(e^{3x)}

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(dy)/(dx)+3y=e^{4x}

\frac{d y}{d x} + 3 y = e^{4 x}

y = \frac{e ^{4 x}}{7} + \frac{c _{1}}{e ^{3 x}}

Solution steps

\frac{d y}{d x} + 3 y = e^{4 x}

Solve linear ODE:

y = \frac{e ^{4 x}}{7} + \frac{c _{1}}{e ^{3 x}}

y = \frac{e ^{4 x}}{7} + \frac{c _{1}}{e ^{3 x}}

n = 0 \sum \infty (\frac{n + 1}{n})^{n}

3 x^{^{''}} - 6 x^{^{'}} + 3 x = 0

x \to 0 + lim (\frac{5}{x} - \frac{5}{∣ x ∣})

y^{^{'}} = \frac{2 y ^{4} + x ^{4}}{x y ^{3}}

\frac{\partial}{\partial x} (2 k^{3} s^{2})

What is the solution for (dy)/(dx)+3y=e^{4x} ?
The solution for (dy)/(dx)+3y=e^{4x} is y=(e^{4x})/7+(c_{1})/(e^{3x)}