What is the limit as x approaches-0 of 1/(x^2) ?

The limit as x approaches-0 of 1/(x^2) is infinity

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limit as x approaches-0 of 1/(x^2)

x \to - 0 lim (\frac{1}{x ^{2}})

\infty

Solution steps

x \to - 0 lim (\frac{1}{x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 0 - lim (\frac{1}{x ^{2}}) = \infty

x \to - 0 + lim (\frac{1}{x ^{2}}) = \infty

= \infty

3 (x^{3} + 1)^{2}

t \to 0 lim (e^{- s t})

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\frac{d}{d x} (x^{2} sin (6 x))

\frac{d}{d x} (ln (x^{2} + x))

What is the limit as x approaches-0 of 1/(x^2) ?
The limit as x approaches-0 of 1/(x^2) is infinity