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Popular >

y^'=-1

Solution

y^{^{'}} = - 1

Solution

y = - t + c_{1}

Solution steps

y^{'} (t) = - 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 1 d t

\int - 1 d t = - t + c_{1}

y = - t + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-1 ?
The solution for y^'=-1 is y=-t+c_{1}