What is the derivative of y=2e^{kx} ?

The derivative of y=2e^{kx} is 2e^{kx}k

What is the first derivative of y=2e^{kx} ?

The first derivative of y=2e^{kx} is 2e^{kx}k

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derivative of

y = 2 e^{k x}

2 e^{k x} k

Solution steps

\frac{d}{d x} (2 e^{k x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{k x})

Apply the chain rule:

e^{k x} \frac{d}{d x} (k x)

= e^{k x} \frac{d}{d x} (k x)

\frac{d}{d x} (k x) = k

= 2 e^{k x} k

\int (tan (x) - cot (x))^{2} d x

(x - 3)^{2} + (y - 1)^{2} = 0

\frac{d}{d x} (sin (f (x)))

\int e^{2 x} sin (π x) d x

y = arcsin (4 x + 1)

What is the derivative of y=2e^{kx} ?
The derivative of y=2e^{kx} is 2e^{kx}k
What is the first derivative of y=2e^{kx} ?
The first derivative of y=2e^{kx} is 2e^{kx}k