What is derivative of f(x)=-5t^3+9t+7 ?

The answer to derivative of f(x)=-5t^3+9t+7 is (dt)/(dx)=0

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derivative of f(x)=-5t^3+9t+7

derivative of

f (x) = - 5 t^{3} + 9 t + 7

\frac{d t}{d x} = 0

Solution steps

f (x) = - 5 t^{3} + 9 t + 7

Treat

t

t (x)

Differentiate both sides:

0 = 9 \frac{d t}{d x} - 15 t^{2} \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{\partial}{\partial x} (x^{3} + y^{3} - 2 x y)

x \to 0 lim (- 4)

g (t) = t^{2} - \frac{4}{t ^{3}}

\int (5 - 2^{- 1}) d x

\frac{d}{d x} (x + cos (x))

What is derivative of f(x)=-5t^3+9t+7 ?
The answer to derivative of f(x)=-5t^3+9t+7 is (dt)/(dx)=0