What is the solution for (-2xy2-1y)dx+(-2x2y+1x)dy=0 ?

The solution for (-2xy2-1y)dx+(-2x2y+1x)dy=0 is y=-(\W(-(4x)/(e^{c_{1)-4x}}))/4

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(-2xy2-1y)dx+(-2x2y+1x)dy=0

(- 2 x y 2 - 1 y) d x + (- 2 x 2 y + 1 x) d y = 0

y = - \frac{W ( - \frac{4 x}{e ^{c_{1} - 4 x}} )}{4}

Solution steps

(- 2 x y 2 - 1 y) d x + (- 2 x 2 y + 1 x) d y = 0

Solve separable ODE:

y = - \frac{W ( - \frac{4 x}{e ^{c_{1} - 4 x}} )}{4}

y = - \frac{W ( - \frac{4 x}{e ^{c_{1} - 4 x}} )}{4}

\frac{d}{d x} (e^{2 x} (2 x - 1))

\int \frac{- 2}{1 + x ^{2}} d x

f (x) = 9 ln (9 + 2 x^{2})

\int cos^{6} (θ) d θ

\frac{d}{d x} (3 - 4 x^{2})

What is the solution for (-2xy2-1y)dx+(-2x2y+1x)dy=0 ?
The solution for (-2xy2-1y)dx+(-2x2y+1x)dy=0 is y=-(\W(-(4x)/(e^{c_{1)-4x}}))/4