What is the derivative of 6/(x^2+2) ?

The derivative of 6/(x^2+2) is -(12x)/((x^2+2)^2)

What is the first derivative of 6/(x^2+2) ?

The first derivative of 6/(x^2+2) is -(12x)/((x^2+2)^2)

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\frac{d}{d x} (\frac{6}{x ^{2} + 2})

- \frac{12 x}{( x ^{2} + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6}{x ^{2} + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{x ^{2} + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((x^{2} + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 2 ) ^{2}} \frac{d}{d x} (x^{2} + 2)

= - \frac{1}{( x ^{2} + 2 ) ^{2}} \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 6 (- \frac{1}{( x ^{2} + 2 ) ^{2}} \cdot 2 x)

Simplify

6 (- \frac{1}{( x ^{2} + 2 ) ^{2}} \cdot 2 x) : - \frac{12 x}{( x ^{2} + 2 ) ^{2}}

= - \frac{12 x}{( x ^{2} + 2 ) ^{2}}

\int_{1}^{7} x^{2} d x

\int arctanh (x) d x

\frac{d y}{d x} = \frac{cos ( x )}{sin ( y )}

f (x) = \frac{1}{1 + x ^{2}}, at x = - 2

\int 6 (x - 7)^{2} d x

What is the derivative of 6/(x^2+2) ?
The derivative of 6/(x^2+2) is -(12x)/((x^2+2)^2)
What is the first derivative of 6/(x^2+2) ?
The first derivative of 6/(x^2+2) is -(12x)/((x^2+2)^2)