What is the slope of f(x)=-2x^4+8x^2 ?

The slope of f(x)=-2x^4+8x^2 is -8x^3+16x

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slope of f(x)=-2x^4+8x^2

slope

f (x) = - 2 x^{4} + 8 x^{2}

- 8 x^{3} + 16 x

Solution steps

f (x) = - 2 x^{4} + 8 x^{2}

In order to find the slope of the function, take the derivative of

- 2 x^{4} + 8 x^{2}

\frac{d}{d x} (- 2 x^{4} + 8 x^{2}) = - 8 x^{3} + 16 x

- 8 x^{3} + 16 x

x \to 0 lim (tan (π x))

\int \frac{1}{( 9 x ^{2} + 4 ) ^{2}} d x

\int - \frac{5}{( x + 2 ) ^{2}} d x

\int \frac{x - 9}{x ^{2} + 3 x - 10} d x

\frac{d}{d x} (arcsin (\frac{x + 1}{2}))

What is the slope of f(x)=-2x^4+8x^2 ?
The slope of f(x)=-2x^4+8x^2 is -8x^3+16x