What is the integral from 0 to pi of (8+5sin(x)) ?

The integral from 0 to pi of (8+5sin(x)) is 8pi+10

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integral from 0 to pi of (8+5sin(x))

\int_{0}^{π} (8 + 5 sin (x)) d x

8 π + 10

Solution steps

\int_{0}^{π} 8 + 5 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 8 d x + \int_{0}^{π} 5 sin (x) d x

\int_{0}^{π} 8 d x = 8 π

\int_{0}^{π} 5 sin (x) d x = 10

= 8 π + 10

x \to - \infty lim (0 - x)

\frac{1 + x ^{2}}{3 x}

\int_{0}^{1} \frac{3}{2} x d x

x^{2} \frac{d y}{d x} - x y = 4 x^{3} sin (x)

\int \frac{( 1 + ln ( x ) )}{x ^{3}} d x

What is the integral from 0 to pi of (8+5sin(x)) ?
The integral from 0 to pi of (8+5sin(x)) is 8pi+10