What is the derivative of 1/5 (9x+8)^3 ?

The derivative of 1/5 (9x+8)^3 is (27(9x+8)^2)/5

What is the first derivative of 1/5 (9x+8)^3 ?

The first derivative of 1/5 (9x+8)^3 is (27(9x+8)^2)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{5} (9 x + 8)^{3}

\frac{27 ( 9 x + 8 ) ^{2}}{5}

Solution steps

\frac{d}{d x} (\frac{1}{5} (9 x + 8)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} ((9 x + 8)^{3})

Apply the chain rule:

3 (9 x + 8)^{2} \frac{d}{d x} (9 x + 8)

= 3 (9 x + 8)^{2} \frac{d}{d x} (9 x + 8)

\frac{d}{d x} (9 x + 8) = 9

= \frac{1}{5} \cdot 3 (9 x + 8)^{2} \cdot 9

Simplify

\frac{1}{5} \cdot 3 (9 x + 8)^{2} \cdot 9 : \frac{27 ( 9 x + 8 ) ^{2}}{5}

= \frac{27 ( 9 x + 8 ) ^{2}}{5}

f (x) = - 4 x^{2} - 5 x + 2

x \to 4 lim (\frac{x - 2}{x - 4})

\int_{0}^{π} x cos (3 x) d x

t^{2} y^{^{''}} + 9 t y^{^{'}} + 7 y = 0

\int \frac{x}{x ^{2} - 3 x + 2} d x

What is the derivative of 1/5 (9x+8)^3 ?
The derivative of 1/5 (9x+8)^3 is (27(9x+8)^2)/5
What is the first derivative of 1/5 (9x+8)^3 ?
The first derivative of 1/5 (9x+8)^3 is (27(9x+8)^2)/5