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Popular >

y^'=2y+e^x

Solution

y^{^{'}} = 2 y + e^{x}

Solution

y = - e^{x} + c_{1} e^{2 x}

Solution steps

y^{'} (x) = 2 y + e^{x}

Solve linear ODE:

y = - e^{x} + c_{1} e^{2 x}

y = - e^{x} + c_{1} e^{2 x}

Popular Examples

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integral of (x^2)/(sqrt(3-x))

\int \frac{x ^{2}}{3 - x} d x

derivative of 3x^2cos(5x)derivative of

3 x^{2} cos (5 x)

derivative of f(x)=xcos(x)-sin(x)derivative of

f (x) = x cos (x) - sin (x)

y^'=-y/(2000+4t)4,y(0)=70

y^{^{'}} = - \frac{y}{2000 + 4 t} 4, y (0) = 70

Frequently Asked Questions (FAQ)

What is the solution for y^'=2y+e^x ?
The solution for y^'=2y+e^x is y=-e^x+c_{1}e^{2x}