What is the integral from 8 to 9 of x/(x-8) ?

The integral from 8 to 9 of x/(x-8) is diverges

Popular >

integral from 8 to 9 of x/(x-8)

\int_{8}^{9} \frac{x}{x - 8} d x

diverges

Solution steps

\int_{8}^{9} \frac{x}{x - 8} d x

Apply u-substitution

: \int_{0}^{1} \frac{u + 8}{u} d u

= \int_{0}^{1} \frac{u + 8}{u} d u

Expand

\frac{u + 8}{u} : 1 + \frac{8}{u}

= \int_{0}^{1} 1 + \frac{8}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d u + \int_{0}^{1} \frac{8}{u} d u

\int_{0}^{1} 1 d u = 1

\int_{0}^{1} \frac{8}{u} d u =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{\partial}{\partial x} (\frac{2 x}{1 + x + 2 y})

f (x) = ln (2 x + 1)

\frac{e ^{x}}{8 x ^{2} + 1}

\int \frac{x}{( 2 + x ^{\frac{3}{2}} ) ^{3}} d x

\int_{1}^{4} 5 - x d x

What is the integral from 8 to 9 of x/(x-8) ?
The integral from 8 to 9 of x/(x-8) is diverges