What is (\partial)/(\partial x)(2xy^7+x^7y^9) ?

The answer to (\partial)/(\partial x)(2xy^7+x^7y^9) is 2y^7+7y^9x^6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2xy^7+x^7y^9)

\frac{\partial}{\partial x} (2 x y^{7} + x^{7} y^{9})

2 y^{7} + 7 y^{9} x^{6}

Solution steps

\frac{\partial}{\partial x} (2 x y^{7} + x^{7} y^{9})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y^{7}) + \frac{\partial}{\partial x} (x^{7} y^{9})

\frac{\partial}{\partial x} (2 x y^{7}) = 2 y^{7}

\frac{\partial}{\partial x} (x^{7} y^{9}) = 7 y^{9} x^{6}

= 2 y^{7} + 7 y^{9} x^{6}

\int 6 tan (6 x) d x

\int + \frac{2}{sec ( 2 x ) - 1} d x

(1 + e^{x}) y^{^{'}} + e^{x} y = 0

y = \frac{1}{x ^{\frac{1}{2}}}

\frac{d y}{d x} = \frac{1 + 2 y ^{2}}{y sin ( x )}

What is (\partial)/(\partial x)(2xy^7+x^7y^9) ?
The answer to (\partial)/(\partial x)(2xy^7+x^7y^9) is 2y^7+7y^9x^6