What is the integral of e^{4x-2} ?

The integral of e^{4x-2} is 1/4 e^{4x-2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{4x-2}

\int e^{4 x - 2} d x

\frac{1}{4} e^{4 x - 2} + C

Solution steps

\int e^{4 x - 2} d x

Apply u-substitution

: \int e^{u} \frac{1}{4} d u

= \int e^{u} \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{4} e^{u}

Substitute back

u = 4 x - 2

= \frac{1}{4} e^{4 x - 2}

Add a constant to the solution

= \frac{1}{4} e^{4 x - 2} + C

x + \frac{6}{x}

\int - cos (x) d x

x^{4} sin (x) tan (x)

x \to 4 lim (\frac{x + 5 - 3}{x - 4})

\frac{d}{d x} (x^{2} n)