What is the solution for (dy)/(dx)+0.8xy=4x ?

The solution for (dy)/(dx)+0.8xy=4x is y=(5e^{(-2x^2+c_{1})/5})/(4)+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+0.8xy=4x

\frac{d y}{d x} + 0.8 x y = 4 x

y = \frac{5 e ^{\frac{- 2 x ^{2} + c _{1}}{5}}}{4} + 5

Solution steps

\frac{d y}{d x} + 0.8 x y = 4 x

Solve separable ODE:

y = \frac{5 e ^{\frac{- 2 x ^{2} + c _{1}}{5}}}{4} + 5

y = \frac{5 e ^{\frac{- 2 x ^{2} + c _{1}}{5}}}{4} + 5

\frac{\partial}{\partial x} (x \cdot i)

y \cdot \frac{d y}{d x} = 5 x (9 + y^{2})

x^{2} e^{x^{2}}

\int_{- 3}^{3} ∣ x + 2 ∣ d x

\int e^{6 x} sin (7 x) d x

What is the solution for (dy)/(dx)+0.8xy=4x ?
The solution for (dy)/(dx)+0.8xy=4x is y=(5e^{(-2x^2+c_{1})/5})/(4)+5