What is area y=2(x+1),y=3(x+1),x=3 ?

The answer to area y=2(x+1),y=3(x+1),x=3 is 8

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area y=2(x+1),y=3(x+1),x=3

area

y = 2 (x + 1), y = 3 (x + 1), x = 3

8

Solution steps

Apply the area formula:

\int_{- 1}^{3} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{3} ∣ x + 1 ∣ d x : 8

The area is:

= 8

\int_{1}^{4} 3 \frac{ln ( x )}{x ^{2}} d x

f (x) = - 6 x^{- 2}

\int_{- 2}^{1} 2 x^{2} + 3 d x

\int sin^{3} (x) cos^{2} (d) x d x

\frac{\partial}{\partial x} (x^{2} \cdot y \cdot z)

What is area y=2(x+1),y=3(x+1),x=3 ?
The answer to area y=2(x+1),y=3(x+1),x=3 is 8