What is the slope of 5/(1+x^2) ?

The slope of 5/(1+x^2) is -(10x)/((1+x^2)^2)

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slope of 5/(1+x^2)

slope

\frac{5}{1 + x ^{2}}

- \frac{10 x}{( 1 + x ^{2} ) ^{2}}

Solution steps

y = \frac{5}{1 + x ^{2}}

In order to find the slope of the function, take the derivative of

\frac{5}{1 + x ^{2}}

\frac{d}{d x} (\frac{5}{1 + x ^{2}}) = - \frac{10 x}{( 1 + x ^{2} ) ^{2}}

- \frac{10 x}{( 1 + x ^{2} ) ^{2}}

\frac{d y}{d x} = (\frac{( 2 y + 5 )}{8 x + 7})^{2}

\int 3 sin (x) cos (x) d x

\frac{\partial}{\partial x} (3 (\frac{( 4 + z )}{5 + x})^{2})

\int x 15 x - 5 d x

\frac{1}{x} d x - \frac{1}{y} d y = 0