What is the solution for 1/y (dy)/(dx)=e^x+log_{e}(y) ?

The solution for 1/y (dy)/(dx)=e^x+log_{e}(y) is y=e^{c_{1}e^x+xe^x}

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1/y (dy)/(dx)=e^x+log_{e}(y)

\frac{1}{y} \frac{d y}{d x} = e^{x} + lo g_{e} (y)

y = e^{c_{1} e^{x} + x e^{x}}

Solution steps

\frac{1}{y} \frac{d y}{d x} = e^{x} + lo g_{e} (y)

Solve exact ODE:

y = e^{c_{1} e^{x} + x e^{x}}

y = e^{c_{1} e^{x} + x e^{x}}

\frac{d}{dd} (d cos (t) + t^{2} sin (t))

\frac{d}{d x} (\frac{sin ( y )}{x})

y^{^{''}} + y^{^{'}} = tan (x)

\int (\frac{1 + x + x}{x}) d x

\int \frac{x}{2 1 + x} d x

What is the solution for 1/y (dy)/(dx)=e^x+log_{e}(y) ?
The solution for 1/y (dy)/(dx)=e^x+log_{e}(y) is y=e^{c_{1}e^x+xe^x}