What is the derivative of f(x)=(ln(x))/2+2 ?

The derivative of f(x)=(ln(x))/2+2 is 1/(2x)

What is the first derivative of f(x)=(ln(x))/2+2 ?

The first derivative of f(x)=(ln(x))/2+2 is 1/(2x)

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derivative of

f (x) = \frac{ln ( x )}{2} + 2

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{ln ( x )}{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (\frac{ln ( x )}{2}) = \frac{1}{2 x}

\frac{d}{d x} (2) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

sin (x)

\int 30 d x

2 x^{2} - 10 x

n = 0 \sum \infty \frac{1}{ln ( n )}

2 - \frac{4}{t} (4.1)

What is the derivative of f(x)=(ln(x))/2+2 ?
The derivative of f(x)=(ln(x))/2+2 is 1/(2x)
What is the first derivative of f(x)=(ln(x))/2+2 ?
The first derivative of f(x)=(ln(x))/2+2 is 1/(2x)