What is the derivative of 3x^3-2 ?

The derivative of 3x^3-2 is 9x^2

What is the first derivative of 3x^3-2 ?

The first derivative of 3x^3-2 is 9x^2

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\frac{d}{d x} (3 x^{3} - 2)

9 x^{2}

Solution steps

\frac{d}{d x} (3 x^{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2) = 0

= 9 x^{2} - 0

Simplify

= 9 x^{2}

n = 0 \sum \infty e^{- 3 n}

\frac{\partial}{\partial x} (\frac{5 x + 4 y}{4 x - y})

\int_{(1 - x)^{2}}^{(1 + x)^{2}} \int_{1}^{3} y e^{x^{2}} d x d y

x \to - 4 - lim (\frac{3 - 8 x}{x + 4})

\frac{d y}{d x}, 2 (x^{2} + y^{2}) 2 = 81 (x^{2} - y^{2})