What is the solution for y^'-5y=6e^{5x},y(0)=0 ?

The solution for y^'-5y=6e^{5x},y(0)=0 is y=6e^{5x}x

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y^'-5y=6e^{5x},y(0)=0

y^{^{'}} - 5 y = 6 e^{5 x}, y (0) = 0

y = 6 e^{5 x} x

Solution steps

y^{'} (x) - 5 y = 6 e^{5 x}

Solve linear ODE:

y = 6 e^{5 x} x

y = 6 e^{5 x} x

\frac{d}{d x} (ln (2 x^{2} - 3 x + 1))

y = x^{2} + 5 x + 6

f (x) = x x, at x = 9

\int cos^{(5)} (5 x) sin (5 x) d x

\int_{0}^{9} 3 x - x d x

What is the solution for y^'-5y=6e^{5x},y(0)=0 ?
The solution for y^'-5y=6e^{5x},y(0)=0 is y=6e^{5x}x