What is area 1/(1+x^2),(x^2)/2 ?

The answer to area 1/(1+x^2),(x^2)/2 is pi/2-1/3

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area 1/(1+x^2),(x^2)/2

area

\frac{1}{1 + x ^{2}}, \frac{x ^{2}}{2}

\frac{π}{2} - \frac{1}{3}

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} - \frac{x ^{2}}{2} d x

Solve

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} - \frac{x ^{2}}{2} d x : \frac{π}{2} - \frac{1}{3}

The area is:

= \frac{π}{2} - \frac{1}{3}

\frac{\partial}{\partial x} (y arctan (\frac{x}{z}))

e^{2 x^{2}}

x \to \infty lim (\frac{7.5 x + 120000}{x})

\int \frac{4}{4 + e ^{4 x}} d x

\frac{\partial}{\partial y} (2 x (3 y^{2} + 2 x^{2}))

What is area 1/(1+x^2),(x^2)/2 ?
The answer to area 1/(1+x^2),(x^2)/2 is pi/2-1/3