What is the derivative of y= 9/x ?

The derivative of y= 9/x is -9/(x^2)

What is the first derivative of y= 9/x ?

The first derivative of y= 9/x is -9/(x^2)

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derivative of

y = \frac{9}{x}

- \frac{9}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 1 \cdot x^{- 1 - 1})

Simplify

9 (- 1 \cdot x^{- 1 - 1}) : - \frac{9}{x ^{2}}

= - \frac{9}{x ^{2}}

\int_{0}^{2} \frac{1}{2} d x

5 x - 4 x

x \to 3 - lim (x^{2} + 2 x)

\int e^{s t} d t

\frac{d}{d x} (8 x^{7})

What is the derivative of y= 9/x ?
The derivative of y= 9/x is -9/(x^2)
What is the first derivative of y= 9/x ?
The first derivative of y= 9/x is -9/(x^2)