What is the integral of 8x^4-5x^3+5x^2+C ?

The integral of 8x^4-5x^3+5x^2+C is (8x^5)/5-(5x^4)/4+(5x^3)/3+Cx+C

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integral of 8x^4-5x^3+5x^2+C

\int 8 x^{4} - 5 x^{3} + 5 x^{2} + C d x

\frac{8 x ^{5}}{5} - \frac{5 x ^{4}}{4} + \frac{5 x ^{3}}{3} + C x + C

Solution steps

\int 8 x^{4} - 5 x^{3} + 5 x^{2} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{4} d x - \int 5 x^{3} d x + \int 5 x^{2} d x + \int C d x

\int 8 x^{4} d x = \frac{8 x ^{5}}{5}

\int 5 x^{3} d x = \frac{5 x ^{4}}{4}

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int C d x = C x

= \frac{8 x ^{5}}{5} - \frac{5 x ^{4}}{4} + \frac{5 x ^{3}}{3} + C x

Add a constant to the solution

= \frac{8 x ^{5}}{5} - \frac{5 x ^{4}}{4} + \frac{5 x ^{3}}{3} + C x + C

\int \frac{3 x ^{2} + 11 v}{v ^{2} - v - 6}

\int (2 x^{2} + 3) e^{6 x} d x

\frac{d}{d x} (\frac{4 x ^{3} - 5}{x ^{2} - 3})

x \to 0 - lim (\frac{6}{x})

\frac{d}{d x} (4 x x)

What is the integral of 8x^4-5x^3+5x^2+C ?
The integral of 8x^4-5x^3+5x^2+C is (8x^5)/5-(5x^4)/4+(5x^3)/3+Cx+C