What is the limit as x approaches 5 of sqrt(x^2-9) ?

The limit as x approaches 5 of sqrt(x^2-9) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of sqrt(x^2-9)

x \to 5 lim (x^{2} - 9)

4

Solution steps

x \to 5 lim (x^{2} - 9)

Plug in the value

x = 5

= 5^{2} - 9

Simplify

5^{2} - 9 : 4

= 4

\frac{d y}{d x} = 7 x 5 y + 3

\frac{d}{d x} (\frac{2000}{sin ( 3 x )})

y = \frac{5 + x f ( x )}{x}

y = 1 - x^{2}, y = 2 x, y = \frac{1}{2} x

\int_{0}^{1} e^{3 x} - e^{x} d x

What is the limit as x approaches 5 of sqrt(x^2-9) ?
The limit as x approaches 5 of sqrt(x^2-9) is 4