What is the derivative of x+(x^2/2) ?

The derivative of x+(x^2/2) is 1+x

What is the first derivative of x+(x^2/2) ?

The first derivative of x+(x^2/2) is 1+x

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\frac{d}{d x} (x + \frac{x ^{2}}{2})

1 + x

Solution steps

\frac{d}{d x} (x + \frac{x ^{2}}{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{x ^{2}}{2})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

= 1 + x

\frac{\partial}{\partial x} (5 x + 3 y)

y = 6 x^{2} + 3 x - 3

(lo g_{5} (x))^{^{'}}

\int_{x}^{x} \frac{e ^{x}}{x} d x

\frac{\partial}{\partial y} (2 x cos (x^{2} + y^{2}))

What is the derivative of x+(x^2/2) ?
The derivative of x+(x^2/2) is 1+x
What is the first derivative of x+(x^2/2) ?
The first derivative of x+(x^2/2) is 1+x