What is the tangent of f(x)=2x^2-7x+5,\at x=2 ?

The tangent of f(x)=2x^2-7x+5,\at x=2 is y=x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2-7x+5,\at x=2

tangent of

f (x) = 2 x^{2} - 7 x + 5, at x = 2

y = x - 3

Solution steps

Find the tangent point:

(2, - 1)

Find the slope of

f (x) = 2 x^{2} - 7 x + 5 : \frac{df ( x )}{d x} = 4 x - 7

Compute the slope of

f (x) = 2 x^{2} - 7 x + 5

x = 2 : m = 1

Find the line with slope m=

1

and passing through

(2, - 1) : y = x - 3

y = x - 3

\frac{d}{d x} (9 ln (1 + x^{2}))

x \to 6 lim (c x^{2} + 7 x)

\int z^{11} d z

\int (cos (x))^{2} (tan (x))^{3} d x

\int \frac{1}{x ( 1000 - x )} d x

What is the tangent of f(x)=2x^2-7x+5,\at x=2 ?
The tangent of f(x)=2x^2-7x+5,\at x=2 is y=x-3