What is the derivative of (x^2-2)^2 ?

The derivative of (x^2-2)^2 is 4x(x^2-2)

What is the first derivative of (x^2-2)^2 ?

The first derivative of (x^2-2)^2 is 4x(x^2-2)

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derivative of

(x^{2} - 2)^{2}

4 x (x^{2} - 2)

Solution steps

\frac{d}{d x} ((x^{2} - 2)^{2})

Apply the chain rule:

2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

= 2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 2 (x^{2} - 2) \cdot 2 x

Simplify

= 4 x (x^{2} - 2)

\frac{\partial}{\partial z} (x y + yz)

\int e^{3 x} (e^{3 x - 8})^{5} d x

y^{^{'}} = 3 x + y

\frac{d ^{3}}{d x ^{3}} (ln (x + 1))

\frac{d y}{d x}, y^{3} = x + y

What is the derivative of (x^2-2)^2 ?
The derivative of (x^2-2)^2 is 4x(x^2-2)
What is the first derivative of (x^2-2)^2 ?
The first derivative of (x^2-2)^2 is 4x(x^2-2)