What is the derivative of (4x^3+3x^2/x) ?

The derivative of (4x^3+3x^2/x) is 8x+3

What is the first derivative of (4x^3+3x^2/x) ?

The first derivative of (4x^3+3x^2/x) is 8x+3

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\frac{d}{d x} (\frac{4 x ^{3} + 3 x ^{2}}{x})

8 x + 3

Solution steps

\frac{d}{d x} (\frac{4 x ^{3} + 3 x ^{2}}{x})

Simplify

\frac{4 x ^{3} + 3 x ^{2}}{x} : x (4 x + 3)

= \frac{d}{d x} (x (4 x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 4 x + 3

= \frac{d x}{d x} (4 x + 3) + \frac{d}{d x} (4 x + 3) x

\frac{d x}{d x} = 1

\frac{d}{d x} (4 x + 3) = 4

= 1 \cdot (4 x + 3) + 4 x

Simplify

= 8 x + 3

sin (x), \frac{1}{2}

f (x) = tan^{40} (sec (cos (x)))

\int 3 sin^{3} (x) d x

y^{^{''}} + 16 y = - 32 sin (4 t)

3 arcsin (x^{3})

What is the derivative of (4x^3+3x^2/x) ?
The derivative of (4x^3+3x^2/x) is 8x+3
What is the first derivative of (4x^3+3x^2/x) ?
The first derivative of (4x^3+3x^2/x) is 8x+3