What is the solution for y^{'''}-8y^{''}-9y^'=0 ?

The solution for y^{'''}-8y^{''}-9y^'=0 is y=c_{1}+c_{2}e^{-t}+c_{3}e^{9t}

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y^{'''}-8y^{''}-9y^'=0

y^{^{'''}} - 8 y^{^{''}} - 9 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- t} + c_{3} e^{9 t}

Solution steps

y^{'''} (t) - 8 y^{''} (t) - 9 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + c_{3} e^{9 t}

y = c_{1} + c_{2} e^{- t} + c_{3} e^{9 t}

\int \frac{cos ^{2} ( θ )}{2} d θ

\int \frac{1}{( 9 - x ^{2} )} d x

\int - 4 x sin (5 x) d x

y = 3 x + 13

x \to \infty lim (9 x^{2})

What is the solution for y^{'''}-8y^{''}-9y^'=0 ?
The solution for y^{'''}-8y^{''}-9y^'=0 is y=c_{1}+c_{2}e^{-t}+c_{3}e^{9t}