What is area 5cos(9x),5-5cos(9x),[0, pi/9 ] ?

The answer to area 5cos(9x),5-5cos(9x),[0, pi/9 ] is (5sqrt(3)pi+90)/(27sqrt(3))

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area 5cos(9x),5-5cos(9x),[0, pi/9 ]

area

5 cos (9 x), 5 - 5 cos (9 x), [0, \frac{π}{9}]

\frac{5 3 π + 90}{27 3}

Decimal

2.50627 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{9}} ∣ 5 cos (9 x) - (5 - 5 cos (9 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{9}} ∣ 5 cos (9 x) - (5 - 5 cos (9 x)) ∣ d x : \frac{5 3 π + 90}{27 3}

The area is:

= \frac{5 3 π + 90}{27 3}

f (x) = (x - 3) (x^{2} - 6 x + 6)

e^{- s} \frac{1}{s}

4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x

\int_{0}^{100} e^{- \frac{x}{0.033}} d x

f (x) = (x^{3} - 2)^{3}

What is area 5cos(9x),5-5cos(9x),[0, pi/9 ] ?
The answer to area 5cos(9x),5-5cos(9x),[0, pi/9 ] is (5sqrt(3)pi+90)/(27sqrt(3))