What is the integral of (cos(x)+1/(cos(x)))^2 ?

The integral of (cos(x)+1/(cos(x)))^2 is 5/2 x+1/4 sin(2x)+tan(x)+C

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integral of (cos(x)+1/(cos(x)))^2

\int (cos (x) + \frac{1}{cos ( x )})^{2} d x

\frac{5}{2} x + \frac{1}{4} sin (2 x) + tan (x) + C

Solution steps

\int (cos (x) + \frac{1}{cos ( x )})^{2} d x

Rewrite using trig identities

= \int \frac{( cos ^{2} ( x ) + 1 ) ^{2}}{cos ^{2} ( x )} d x

Expand

\frac{( cos ^{2} ( x ) + 1 ) ^{2}}{cos ^{2} ( x )} : cos^{2} (x) + 2 + \frac{1}{cos ^{2} ( x )}

= \int cos^{2} (x) + 2 + \frac{1}{cos ^{2} ( x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos^{2} (x) d x + \int 2 d x + \int \frac{1}{cos ^{2} ( x )} d x

\int cos^{2} (x) d x = \frac{1}{2} (x + \frac{1}{2} sin (2 x))

\int 2 d x = 2 x

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= \frac{1}{2} (x + \frac{1}{2} sin (2 x)) + 2 x + tan (x)

Simplify

\frac{1}{2} (x + \frac{1}{2} sin (2 x)) + 2 x + tan (x) : \frac{5}{2} x + \frac{1}{4} sin (2 x) + tan (x)

= \frac{5}{2} x + \frac{1}{4} sin (2 x) + tan (x)

Add a constant to the solution

= \frac{5}{2} x + \frac{1}{4} sin (2 x) + tan (x) + C

\frac{9}{x ^{2}}, 1

\frac{e ^{x}}{2}, 0, 0, 2

\frac{\partial}{\partial y} (10 x^{9} y^{9} + 3)

\frac{\partial}{\partial y} (\frac{5}{y})

What is the integral of (cos(x)+1/(cos(x)))^2 ?
The integral of (cos(x)+1/(cos(x)))^2 is 5/2 x+1/4 sin(2x)+tan(x)+C