What is the derivative of 2sec(2xtan(2x)) ?

The derivative of 2sec(2xtan(2x)) is 2(2tan^2(2x)sec(2x)+2sec^3(2x))

What is the first derivative of 2sec(2xtan(2x)) ?

The first derivative of 2sec(2xtan(2x)) is 2(2tan^2(2x)sec(2x)+2sec^3(2x))

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\frac{d}{d x} (2 sec (2 x) tan (2 x))

2 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

Solution steps

\frac{d}{d x} (2 sec (2 x) tan (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec (2 x) tan (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec (2 x), g = tan (2 x)

= 2 (\frac{d}{d x} (sec (2 x)) tan (2 x) + \frac{d}{d x} (tan (2 x)) sec (2 x))

\frac{d}{d x} (sec (2 x)) = sec (2 x) tan (2 x) \cdot 2

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= 2 (sec (2 x) tan (2 x) \cdot 2 tan (2 x) + sec^{2} (2 x) \cdot 2 sec (2 x))

Simplify

2 (sec (2 x) tan (2 x) \cdot 2 tan (2 x) + sec^{2} (2 x) \cdot 2 sec (2 x)) : 2 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

= 2 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

0.125 x 64 - x^{2}

\frac{\partial}{\partial x} (x^{2} + sin (x y))

\frac{d}{d x} (a cos (b x))

\int 4 x - \frac{4}{x} d x

\int_{1}^{4} (x^{2} + \frac{1}{4 x ^{2}}) d x

What is the derivative of 2sec(2xtan(2x)) ?
The derivative of 2sec(2xtan(2x)) is 2(2tan^2(2x)sec(2x)+2sec^3(2x))
What is the first derivative of 2sec(2xtan(2x)) ?
The first derivative of 2sec(2xtan(2x)) is 2(2tan^2(2x)sec(2x)+2sec^3(2x))