What is the sum from n=0 to infinity of 1/(2^{2n-1)} ?

The sum from n=0 to infinity of 1/(2^{2n-1)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/(2^{2n-1)}

n = 0 \sum \infty \frac{1}{2 ^{2 n - 1}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{2 ^{2 n - 1}}

Apply Series Ratio Test:

converges

= converges

\int_{0}^{a} \frac{1}{( a + r - x ) ^{2}} d x

x, x^{3}

\int \frac{sin ( x )}{cos ^{6} ( x )} d x

- \frac{20}{s ( s + 10 )}

y = 2 x^{3} + 3 x^{2} - 12 x + 3

What is the sum from n=0 to infinity of 1/(2^{2n-1)} ?
The sum from n=0 to infinity of 1/(2^{2n-1)} is converges