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Popular >

y^'=(1-y)cos(x)

Solution

y^{^{'}} = (1 - y) cos (x)

Solution

y = - e^{- s i n (x) - c_{1}} + 1

Solution steps

y^{'} (x) = (1 - y) cos (x)

Solve separable ODE:

y = - e^{- s i n (x) - c_{1}} + 1

y = - e^{- s i n (x) - c_{1}} + 1

Popular Examples

integral of y/(sqrt(x))

\int \frac{y}{x} d x

tangent of y=(x^3-16x)^8,(-4,0)tangent of

y = (x^{3} - 16 x)^{8}, (- 4, 0)

(dy)/(dx)=(x+y)

\frac{d y}{d x} = (x + y)

derivative of x(ln(x^2))

\frac{d}{d x} (x (ln (x^{2})))

integral of sin^6(2x)

\int sin^{6} (2 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(1-y)cos(x) ?
The solution for y^'=(1-y)cos(x) is y=-e^{-sin(x)-c_{1}}+1