What is the derivative of 4x^2-2x-1 ?

The derivative of 4x^2-2x-1 is 8x-2

What is the first derivative of 4x^2-2x-1 ?

The first derivative of 4x^2-2x-1 is 8x-2

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derivative of

4 x^{2} - 2 x - 1

8 x - 2

Solution steps

\frac{d}{d x} (4 x^{2} - 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 8 x - 2 - 0

Simplify

= 8 x - 2

y^{^{'}} = e^{y}

x \to 2 lim (\frac{x + 1}{2 - x})

\int 4 x^{\frac{1}{3}} d x

\frac{d}{d x} (4 sin (2 x) - 3 cos (3 x))

\int_{- 2}^{0} - x^{2} - 2 x d x

What is the derivative of 4x^2-2x-1 ?
The derivative of 4x^2-2x-1 is 8x-2
What is the first derivative of 4x^2-2x-1 ?
The first derivative of 4x^2-2x-1 is 8x-2