What is the slope ofintercept (-8,-4),(-6,-1) ?

The slope ofintercept (-8,-4),(-6,-1) is y= 3/2 x+8

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slope ofintercept (-8,-4),(-6,-1)

slope intercept

(- 8, - 4), (- 6, - 1)

y = \frac{3}{2} x + 8

Solution steps

Compute the slope

(- 8, - 4), (- 6, - 1) : m = \frac{3}{2}

Compute the

y

intercept:

b = 8

Construct the line equation

y = mx + b

where

m = \frac{3}{2}

and

b = 8

y = \frac{3}{2} x + 8

y = \frac{4}{3} x + 2

x \to \infty lim (\frac{+ x - 2 ^{+ x}}{3 ^{x} - 5})

\int 5 \frac{cos ( x ) + sin ( x )}{sin ( 2 x )} d x

f (x) = \frac{x}{x ^{2} + 81}

\int_{0}^{1} (1 - x^{3}) d x

What is the slope ofintercept (-8,-4),(-6,-1) ?
The slope ofintercept (-8,-4),(-6,-1) is y= 3/2 x+8