What is the tangent of y=ln(x^2),(5,ln(25)) ?

The tangent of y=ln(x^2),(5,ln(25)) is y= 2/5 x+2ln(5)-2

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tangent of y=ln(x^2),(5,ln(25))

tangent of

y = ln (x^{2}), (5, ln (25))

y = \frac{2}{5} x + 2 ln (5) - 2

Solution steps

Find the slope of

y = ln (x^{2}) : \frac{d y}{d x} = \frac{2}{x}

Compute the slope of

y = ln (x^{2})

(5, ln (25)) : m = \frac{2}{5}

Find the line with slope m=

\frac{2}{5}

and passing through

(5, ln (25)) : y = \frac{2}{5} x + 2 ln (5) - 2

y = \frac{2}{5} x + 2 ln (5) - 2

f (x) = 3 x^{8}

x \to 0 lim (x^{s i n (2 x)})

\frac{\partial}{\partial x} (\frac{4 x}{y ^{3}})

x - y d x + x d y = 0

What is the tangent of y=ln(x^2),(5,ln(25)) ?
The tangent of y=ln(x^2),(5,ln(25)) is y= 2/5 x+2ln(5)-2