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Popular >

integral of 1+y

Solution

\int 1 + y d y

Solution

y + \frac{y ^{2}}{2} + C

Solution steps

\int 1 + y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d y + \int y d y

\int 1 d y = y

\int y d y = \frac{y ^{2}}{2}

= y + \frac{y ^{2}}{2}

Add a constant to the solution

= y + \frac{y ^{2}}{2} + C

Popular Examples

limit as x approaches 0 of (3x^2)/x

x \to 0 lim (\frac{3 x ^{2}}{x})

derivative of y=(x^3-3x)(2x^2+3x+5)derivative of

y = (x^{3} - 3 x) (2 x^{2} + 3 x + 5)

limit as x approaches 0+of x(ln(x^2))

x \to 0 + lim (x (ln (x^{2})))

derivative of sqrt((3sin(x-2cos(x))/5))

\frac{d}{d x} (\frac{3 sin ( x ) - 2 cos ( x )}{5})

integral of (cos(x))^2sin(x)

\int (cos (x))^{2} sin (x) d x

Frequently Asked Questions (FAQ)

What is the integral of 1+y ?
The integral of 1+y is y+(y^2)/2+C