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Popular >

area x=y^2,x=4

Solution

area

x = y^{2}, x = 4

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Isolate

y

for

x = y^{2} : y = x, y = - x

Apply the area formula:

\int_{0}^{4} 2 x d x

Solve

\int_{0}^{4} 2 x d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

integral of (3x^2-2x+1)(x^3-x^2+x)^3

\int (3 x^{2} - 2 x + 1) (x^{3} - x^{2} + x)^{3} d x

integral of \sqrt[3]{3-5x^2}(-10x)

derivative of y=(9+xf(x))/(sqrt(x))derivative of

y = \frac{9 + x f ( x )}{x}

derivative of 3x^2sin(x)

\frac{d}{d x} (3 x^{2} sin (x))

derivative of x/(sqrt(x^2+2))

\frac{d}{d x} (\frac{x}{x ^{2} + 2})

Frequently Asked Questions (FAQ)

What is area x=y^2,x=4 ?
The answer to area x=y^2,x=4 is 32/3