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Popular >

integral of (2t-1)

Solution

\int (2 t - 1) d t

Solution

t^{2} - t + C

Solution steps

\int 2 t - 1 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 t d t - \int 1 d t

\int 2 t d t = t^{2}

\int 1 d t = t

= t^{2} - t

Add a constant to the solution

= t^{2} - t + C

Popular Examples

integral of (sqrt(2-x^2))

\int (2 - x^{2}) d x

y y^{^{'}} - e^{x} = 0

tangent of y=3-x^3(0.3)tangent of

y = 3 - x^{3} (0.3)

derivative of log_{10}(2x-1)

\frac{d}{d x} (lo g_{10} (2 x - 1))

integral of x^2(x^3-1)^2

\int x^{2} (x^{3} - 1)^{2} d x

Frequently Asked Questions (FAQ)

What is the integral of (2t-1) ?
The integral of (2t-1) is t^2-t+C