What is the derivative of 322560(2x+5) ?

The derivative of 322560(2x+5) is 645120

What is the first derivative of 322560(2x+5) ?

The first derivative of 322560(2x+5) is 645120

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (322560 (2 x + 5))

645120

Solution steps

\frac{d}{d x} (322560 (2 x + 5))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 322560 \frac{d}{d x} (2 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 322560 (\frac{d}{d x} (2 x) + \frac{d}{d x} (5))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (5) = 0

= 322560 (2 + 0)

Simplify

= 645120

\int x 3 - x^{2} - x^{2} d x

\int \frac{x}{3 x + 2} d x

r \to 0 lim (r^{2} ln (r^{2}))

\int 8 z d z

x \to \infty lim (2 (- 23 e^{- x} + 23 e^{- 1}))

What is the derivative of 322560(2x+5) ?
The derivative of 322560(2x+5) is 645120
What is the first derivative of 322560(2x+5) ?
The first derivative of 322560(2x+5) is 645120