What is the derivative of e^x+x ?

The derivative of e^x+x is e^x+1

What is the first derivative of e^x+x ?

The first derivative of e^x+x is e^x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{x} + x)

e^{x} + 1

Solution steps

\frac{d}{d x} (e^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d x}{d x} = 1

= e^{x} + 1

(x - y) d x - (x + y) d y = 0

\int \frac{3}{x ^{2} - 8 x + 6} d x

k = 0 \sum \infty x^{k + 1}

y = (3 x + 8) x^{2}

x \to 2 - lim (x^{2} + 1)