What is area y=7+2sqrt(x),y=(14+x)/2 ?

The answer to area y=7+2sqrt(x),y=(14+x)/2 is 64/3

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area y=7+2sqrt(x),y=(14+x)/2

area

y = 7 + 2 x, y = \frac{14 + x}{2}

\frac{64}{3}

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{16} 7 + 2 x - \frac{14 + x}{2} d x

Solve

\int_{0}^{16} 7 + 2 x - \frac{14 + x}{2} d x : \frac{64}{3}

The area is:

= \frac{64}{3}

\int (cos^{3} (2 x)) d x

\int x^{- \frac{3}{2}} d x

\frac{d}{d x} (x^{2} cos (x^{2}))

\int_{0}^{3} y + 1 d y

f (x) = x^{3} + 3 x - 6, (1, - 2)

What is area y=7+2sqrt(x),y=(14+x)/2 ?
The answer to area y=7+2sqrt(x),y=(14+x)/2 is 64/3