What is the limit as x approaches 0 of ((3^x-2^x))/x ?

The limit as x approaches 0 of ((3^x-2^x))/x is ln(3)-ln(2)

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limit as x approaches 0 of ((3^x-2^x))/x

x \to 0 lim (\frac{( 3 ^{x} - 2 ^{x} )}{x})

ln (3) - ln (2)

Decimal

0.40546 \dots

Solution steps

x \to 0 lim (\frac{3 ^{x} - 2 ^{x}}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{3 ^{x} ln ( 3 ) - 2 ^{x} ln ( 2 )}{1})

= x \to 0 lim (\frac{3 ^{x} ln ( 3 ) - 2 ^{x} ln ( 2 )}{1})

Plug in the value

x = 0

= \frac{3 ^{0} ln ( 3 ) - 2 ^{0} ln ( 2 )}{1}

Simplify

\frac{3 ^{0} ln ( 3 ) - 2 ^{0} ln ( 2 )}{1} : ln (3) - ln (2)

= ln (3) - ln (2)

\int (e^{2 x} + e^{- 3 x}) d x

(ln (x))^{5}

\int \frac{x - 2 x ^{2} + 1}{x} d x

r \to \infty lim (ln (r))

\int \frac{( x - 1 )}{( x ^{3} - x ^{2} - 2 x )} d x

What is the limit as x approaches 0 of ((3^x-2^x))/x ?
The limit as x approaches 0 of ((3^x-2^x))/x is ln(3)-ln(2)