What is the solution for y^{''}-9y^'=7t ?

The solution for y^{''}-9y^'=7t is y=c_{1}e^{9t}+c_{2}-(7t^2)/(18)-(7t)/(81)

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y^{''}-9y^'=7t

y^{^{''}} - 9 y^{^{'}} = 7 t

y = c_{1} e^{9 t} + c_{2} - \frac{7 t ^{2}}{18} - \frac{7 t}{81}

Solution steps

y^{''} (t) - 9 y^{'} (t) = 7 t

Solve linear ODE:

y = c_{1} e^{9 t} + c_{2} - \frac{7 t ^{2}}{18} - \frac{7 t}{81}

y = c_{1} e^{9 t} + c_{2} - \frac{7 t ^{2}}{18} - \frac{7 t}{81}

f (x) = \frac{tan ( x ^{2} )}{4}

y = \frac{x ^{8}}{f ( x )}

\int 5 cot^{5} (θ) sin^{4} (θ) d θ

9 x

\frac{\partial}{\partial x} (lo g_{10} (x + 1))

What is the solution for y^{''}-9y^'=7t ?
The solution for y^{''}-9y^'=7t is y=c_{1}e^{9t}+c_{2}-(7t^2)/(18)-(7t)/(81)