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Popular >

(x^2-4)y^'=-2xy^2

Solution

(x^{2} - 4) y^{^{'}} = - 2 x y^{2}

Solution

y = - \frac{1}{- ln ( x ^{2} - 4 ) + c _{1}}

Solution steps

(x^{2} - 4) y^{'} (x) = - 2 x y^{2}

Solve separable ODE:

y = - \frac{1}{- ln ( x ^{2} - 4 ) + c _{1}}

y = - \frac{1}{- ln ( x ^{2} - 4 ) + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (x^2-4)y^'=-2xy^2 ?
The solution for (x^2-4)y^'=-2xy^2 is y=-1/(-ln(x^2-4)+c_{1)}