What is the sum from n=1 to infinity of (cos(2.6))^n ?

The sum from n=1 to infinity of (cos(2.6))^n is converges

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sum from n=1 to infinity of (cos(2.6))^n

n = 1 \sum \infty (cos (2.6))^{n}

converges

Solution steps

n = 1 \sum \infty (cos (2.6))^{n}

Simplify

cos (2.6) : - 0.85688 \dots

= n = 1 \sum \infty (- 0.85688 \dots)^{n}

Apply Series Ratio Test:

converges

= converges

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n = 0 \sum \infty n! (x - 5)^{n}

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What is the sum from n=1 to infinity of (cos(2.6))^n ?
The sum from n=1 to infinity of (cos(2.6))^n is converges