What is (\partial)/(\partial x)(xln(z^7+x^4)) ?

The answer to (\partial)/(\partial x)(xln(z^7+x^4)) is ln(z^7+x^4)+(4x^4)/(z^7+x^4)

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(\partial)/(\partial x)(xln(z^7+x^4))

\frac{\partial}{\partial x} (x ln (z^{7} + x^{4}))

ln (z^{7} + x^{4}) + \frac{4 x ^{4}}{z ^{7} + x ^{4}}

Solution steps

\frac{\partial}{\partial x} (x ln (z^{7} + x^{4}))

Treat

z

as a constant

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = ln (z^{7} + x^{4})

= \frac{\partial}{\partial x} (x) ln (z^{7} + x^{4}) + \frac{\partial}{\partial x} (ln (z^{7} + x^{4})) x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (ln (z^{7} + x^{4})) = \frac{4 x ^{3}}{z ^{7} + x ^{4}}

= 1 \cdot ln (z^{7} + x^{4}) + \frac{4 x ^{3}}{z ^{7} + x ^{4}} x

Simplify

1 \cdot ln (z^{7} + x^{4}) + \frac{4 x ^{3}}{z ^{7} + x ^{4}} x : ln (z^{7} + x^{4}) + \frac{4 x ^{4}}{z ^{7} + x ^{4}}

= ln (z^{7} + x^{4}) + \frac{4 x ^{4}}{z ^{7} + x ^{4}}

y = x^{2} - 4 x - 3, (3, - 6)

(\frac{1}{x}), (\frac{1}{x ^{2}}), 2

y = 4 x^{2} + 3 y^{2} + 8 x - 6 y - 45, (- 2, - 3)

\frac{4 x ^{2} + 6 x + 4}{x}

f (x) = \frac{x ^{3} e ^{x}}{1 - x}

What is (\partial)/(\partial x)(xln(z^7+x^4)) ?
The answer to (\partial)/(\partial x)(xln(z^7+x^4)) is ln(z^7+x^4)+(4x^4)/(z^7+x^4)